SQL练习八
有一个全部员工的薪水表salaries简况如下:
有一个各个部门的领导表dept_manager简况如下:
请你查找各个部门当前领导的薪水详情以及其对应部门编号dept_no，输出结果以salaries.emp_no升序排序，并且请注意输出结果里面dept_no列是最后一列，以上例子输出如下:
表结构
drop table if exists `salaries` ;drop table if exists `dept_manager` ;CREATE TABLE `salaries` (`emp_no` int(11) NOT NULL,`salary` int(11) NOT NULL,`from_date` date NOT NULL,`to_date` date NOT NULL,PRIMARY KEY (`emp_no`,`from_date`));CREATE TABLE `dept_manager` (`dept_no` char(4) NOT NULL,`emp_no` int(11) NOT NULL,`to_date` date NOT NULL,PRIMARY KEY (`emp_no`,`dept_no`));
SQL语句
INSERT INTO dept_manager VALUES('d001',10002,'9999-01-01');INSERT INTO dept_manager VALUES('d002',10006,'9999-01-01');INSERT INTO dept_manager VALUES('d003',10005,'9999-01-01');INSERT INTO dept_manager VALUES('d004',10004,'9999-01-01');INSERT INTO salaries VALUES(10001,88958,'2002-06-22','9999-01-01');INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01');INSERT INTO salaries VALUES(10003,43311,'2001-12-01','9999-01-01');INSERT INTO salaries VALUES(10004,74057,'2001-11-27','9999-01-01');INSERT INTO salaries VALUES(10005,94692,'2001-09-09','9999-01-01');INSERT INTO salaries VALUES(10006,43311,'2001-08-02','9999-01-01');INSERT INTO salaries VALUES(10007,88070,'2002-02-07','9999-01-01');
答案：
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